Question

Identify a relationship among Tn ,Sn and Sn-1 where n>1 and n€N

Answer 1

Step-by-step explanation:

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Answer 2

We know that

In a sequence: a1 , a2 , a3 , a4 +........ , an

Tn = an

Sn = a1+a2+a3+a4+........ +a(n-1)+an

Sn-1 = a1+ a2+a3+........ +a(n-1)

Given: n>1 and n€N

To find a relation between Sn, Sn-1 and Tn

Solution:

Sn - Sn-1 = a1+a2+... a(n-1) +an -

(a1+a2+..... a(n-1))

=an

Therefore, Sn - S(n-1) is equal to an.