Question

Identify after simplification wheather the equation (x-2) (x+2) = 12 is. A quadratic or not

Answer 1

Answer:

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Answer 2

$\large{\underline{\underline{\red{\sf{GIVEN:}}}}}$

• A equation is given to us i.e. (x-2)(x+2)=12.

$\large{\underline{\underline{\red{\sf{TO\: CHECK:}}}}}$

• To check after simplification it is quadratic equation or not.

$\large{\underline{\underline{\red{\sf{CONCEPT\:USED:}}}}}$

• Firstly we will simplify the equation.
• Secondly we will check the highest degree of the variable .

$\large{\underline{\underline{\red{\sf{ANSWER:}}}}}$

We are here given a quadratic equation which is (x+2)(x-2)=12.

Now on simplification ,

$\sf{\implies (x+2)(x-2)=12}$

$\sf{\implies x^{2}-(2)^{2}=12}$

using

• (a+b)(a-b)=a²-b².

$\sf{\implies x^{2}-4=12}$

$\sf{\implies x^{2}-4-12=0}$

${\underline{\boxed{\red{\sf{\leadsto x^{2}-16=0}}}}}$

$\rule{200}1$

Now ,after simplification we got the equation as x²-16=0 .

Here highest degree of the variable is 2 .

Hence the given equation is a quadratic equation.