Identify an equation in point-slope form for the line parallel to y=-(2)/(3)x+8 that passes through (4,-5)
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Parallel lines have same slopes.
Given,
Our required line equation is parallel to
y = -2x/3 + 8
So slope of our required line is -2/3
Equation of a line passing through the point (x1,y1) and having slope m is
y - y1 = m(x - x1)
Here point is (4,-5) and slope is -2/3
y - 4 = -2/3 (x - (-5))
3y - 12 = - 2x - 10
3y = - 2x + 2
2x + 3y = 2 is the required equation.
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