Question

Identify B in the following reaction.
Methyl cyanide on reduction in presence of Na/C2H5OH gives compound A which on further reacting with NaNO2 & HCl gives B :

a) CH3-CH2-NH2
b) CH3-CH2-NO2
c) CH3-CH2 N2+ Cl-
d) CH3-CH2-OH​

Answer 1

Answer:

Ethylamine

Nitro ethane

Explanation:

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Answer 2

Answer:

Methyl cyanide CH₃-CN on reduction in presence of Na/C₂H₅OH gives CH₃CH₂NH₂  which on further reacting with NaNO₂ and HCl gives diazonium salt CH₃CH₂N₂⁺ Cl⁻.

Therefore, the option (c) is correct.

Explanation:

• In the presence of alcohol, methyl cyanide reacts with sodium atom. The reduction of nitrile take place. The formation of primary amine as product. This reaction is actually a named reaction which is Mendius reaction.

            $CH_{3}-CN\;\;\;\underrightarrow{Na/C_{2}H_{5}OH}\; \; CH_{3}CH_{2}NH_{2}$

• The further reaction of formed aliphatic primary amine with sodium nitrite NaNO₂ and HCl will give diazonium salt.

          CH₃CH₂NH₂   +   NaNO₂/HCl   $\longrightarrow$    CH₃CH₂N₂⁺  Cl⁻

         Primary amine                                      diazonium salt

        Formed diazonium salt is actually unstable so, it gives carbocation which further participate in reactions.