Question

Identify disproportionation reaction
(a) $CH_4 + 2O_2 \longrightarrow CO_2 + 2H_2O$
(b) $CH_4 + 4Cl_2 \longrightarrow CCl_4 + 4HCl$
(c) $2F_2 + 2OH^- \longrightarrow 2F^- + OF_2 + H_2O$
(d) $2NO_2 + 2OH^- \longrightarrow NO_2^- + NO_3^- + H_2O$

Answer 1

answer is c option because f exhibits two oxidation state s

Answer 2

Answer:d

Explanation:

In case of NO2 oxidation state of nitrogen Is +4 where as in case of NO2- and NO3- is +3 and +5 respectively.

Disproportionation reaction is that reaction in which single element undergoes oxidation and reduction both.