Identify dobereiner's triads from the following group of elements having similar chemical properties. B(9.0),Mg(24.3),Ca(40.1)
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Answer. Dobereiner's triad are:- Be(9.0), Mg(24.3), Ca(40.1) as:- The avg. mass of Be and Ca=(9+24.3)/2=24.3 which is the mass of Mg. Therefore, these elements have similar chemical properties
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(i) (a) Mg (24.3), (b) Ca (40.1), (c) Sr (87.6)
∴ mean of a + c
2 = 111.90
2
= 55.95
which is not approximately equal to the atomic
mass of middle element (Ca). Therefore, it does
not form Dobereiner’s triads.
(ii) (a) S (32.1), (b) Se (79.0), (c) Te (127.6)
∴ mean of a + c
2 = 159.70
2
= 79.85
which is approximately equal to atomic mass of
Se. Hence, it forms Dobereiner’s triads.
(iii) (a) Be (9.0), (b) Mg (24.3), (c) Ca (40.1)
∴ mean of a + c
2 = 49.10
2
= 24.55
which is approximately equal to atomic mass of
Mg. Hence, it forms Dobereiner’s triads.
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