Identify from the following reaction : H2S + Cl2 → 2HCl + S a. Component oxidized b. Oxidizing agent
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Method 1
If we see the reactant and product, we will find that, there is removal of H from H₂S to S, so H₂S is oxidized S.
Whereas there is addition of H from Cl₂ to HCl, so Cl₂ is reduced.
Hence, Cl₂ will be the oxidizing agent, which itself get reduced.
Method 2
Oxidation number method
reactant product
H = +1 H= +1
S= -2 S= 0 -------oxidized
Cl = 0 Cl = -1--------- reduced, hence oxidizing agent
If we see the reactant and product, we will find that, there is removal of H from H₂S to S, so H₂S is oxidized S.
Whereas there is addition of H from Cl₂ to HCl, so Cl₂ is reduced.
Hence, Cl₂ will be the oxidizing agent, which itself get reduced.
Method 2
Oxidation number method
reactant product
H = +1 H= +1
S= -2 S= 0 -------oxidized
Cl = 0 Cl = -1--------- reduced, hence oxidizing agent
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