Identify from the following reaction the reactants that undergo oxidation and reduction. a. Fe + S ---> FeS b. 2Ag2O ---> 4Ag + O2^ c. 2Mg + O2 --->2MgO d. NiO + H2 ---> Ni + H2O PLZZ ANSWER FAST AS IT'S URGENT... IF YOU WANT BRAINLIEST AND 10 POINTS.
Answers
Answer:
A. Fe is undergoing oxidation and sulphur is 7ndergoing reduction.
B. Ag2O is getting reduced.
C. Mg is getting oxidised and O2 is getting reduced
D. NiO is getting reduced and H2 is getting oxidised.
Explanation:
in A Fe is getting added to a non metal which is definition of oxidation whereas sulphur is getting added to iron which is a metal so it is undergoing reduction. Moreover you can apply electronic concept also which is: if an element gains electrons like that of a non metal then it undergoes reduction and if it looses then it's oxidation.
B . Ag2O gets decomposed to Ag and O2 so it's loosing O2 therefore it's reduction.
C Mg is added to oxygen so it's oxidation and oxygen is added to a metal so it's reduction.
D NiO is loosing O2 so it's reduction and H2 is gaining oxygen so it's oxidation.
theory:
oxidation is gain in oxidation number/ loss of electron/gain of oxygen/loss of hydrogen.
reduction: decrease in oxidation number/gain of electron/loss of oxygen atom/gain of hydrogen
in elementary state, oxidation number=0
Explanation:
Fe⁰+ S⁰---->Fe⁺²S⁻²
Fe goes from 0 to 2 hence oxidation
S goes from 0 to -2 hence reduction
2Ag⁺¹₂O⁻² ---->4Ag⁰ +O⁰₂
Ag goes from 1 to 0 hence reduction
O₂ goes from -2 to 0 hence oxidation
2Mg⁰ + O⁰₂ --->2Mg⁺²O²⁻
Mg goes from 0 to 2 hence oxidation
O₂ goes from 0 to -2 hence reduction
Ni²O⁻² + H⁰₂ ---> Ni⁰ + H¹₂O⁻²
Ni goes from 2 to 0 hence reduction
H₂ goes from 0 to 1 hence oxidation
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hope it helped !!!