Question

identify linear equation in one variable x2+1=y+y2,1+z+z2+z3,2x-3=7​

Answer 1

Answer:

Let's solve for x.

x2+1=y+y2

Step 1: Add -1 to both sides.

x2+1+−1=y2+y+−1

x2=y2+y−1

Step 2: Take square root.

x=√y2+y−1 or x=−√y2+y−1

Answer:

x=√y2+y−1 or x=−√y2+y−1

Let's simplify step-by-step.

1+z+z2+z3

Answer:

=z3+z2+z+1

Let's solve your equation step-by-step.

2x−3=7

Step 1: Add 3 to both sides.

2x−3+3=7+3

2x=10

Step 2: Divide both sides by 2.

2x/2=10/2

x=5

Answer:

x=5