Identify one cation and one anion in the given unknown salt m1 by performing dry tests practical
Answers
Answer:
Atomic weight of the gold is = 196. 97(197g approx) That means 6.022×10^23 atoms weigh 196.97 g.
Cation and one anion in the given unknown salt M1 can be detected with the help of dry and wet test of ions
Explanation:
Identification of radical by DRY Test:-
• In this small amount of salt is used and is observed for colour, small moisture
• The temperature should be room temperature at which the study is done.
• Carbonate, sulphide, sulphite, nitrite and acetate reacts with sulphuric acid to evolve various gases.
• The evolved gases is studied to collect the information of anionic radicals
Identification of radical by WET Test
• A Confirmatory test of anions is carried out by dissolving in water. It is soluble in water and then using sodium carbonate extract.
• Using sodium extract the confirmatory test of anions is done
Qualitative analysis can be used to determine the cation and anion in the salt.