Question

identify oxidising and reducing agent in the following equation
MnCl2 +Na2S —MnS +2NaCl​

Answer 1

this is answer of this question

Answer 2

MnCl2 is the oxidising agent in this reaction, while Na2S is the reducing agent.

As per the question given,

In a redox reaction, one species loses electrons and is oxidized, while another species gains electrons and is reduced. The species that loses electrons is called the oxidizing agent, while the species that gains electrons is called the reducing agent.

In the reaction, MnCl2 + Na2S -> MnS + 2NaCl, we can see that Mn goes from a state of oxidation of +2 in MnCl2 to a state of oxidation of 0 in MnS. This means that Mn has been reduced, so it is the reducing agent. Meanwhile, Na goes from a state of oxidation of +1 in NaCl to a state of oxidation of +2 in Na2S. This means that Na has been oxidized, so it is the oxidizing agent.

So, in this reaction, MnCl2 is the oxidizing agent, while Na2S is the reducing agent.

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