Question

Identify the bonds present between the given molecules A and B.

Answer 1

Answer:

Compound A is actually a polysaccharide consisting of more than 2 sugar units.

These monomeric units are bound to one another via the following linkage :

$\: \: \: \: \: \: \: \: \: \boxed{ \sf{ \red{ \large{Glycosidic \: Linkage}}}}$

• Glycosidic linkages are ether linkages formed by the Hydroxyl group of adjacent Sugar units.

Compound B is actually a Di-peptide , consisting of 2 Amino acids . This type of linkages are seen in formation of Proteins , where series of Amino acids are bound to one another in Primary Structure.

So the linkage present here is :

$\: \: \: \: \: \: \: \: \: \boxed{ \sf{ \red{ \large{Peptide \: Linkage}}}}$

• Peptide linkage is actually an amide linkage formed between Carboxyl group of one Amino acid and the Amino group of other Amino acid.

Answer 2

Answer:

Compound A is actually a polysaccharide consisting of more than 2 sugar units.

These monomeric units are bound to one another via the following linkage :

\: \: \: \: \: \: \: \: \: \boxed{ \sf{ \red{ \large{Glycosidic \: Linkage}}}}

GlycosidicLinkage

Glycosidic linkages are ether linkages formed by the Hydroxyl group of adjacent Sugar units.

Compound B is actually a Di-peptide , consisting of 2 Amino acids . This type of linkages are seen in formation of Proteins , where series of Amino acids are bound to one another in Primary Structure.

So the linkage present here is :

\: \: \: \: \: \: \: \: \: \boxed{ \sf{ \red{ \large{Peptide \: Linkage}}}}

PeptideLinkage

Peptide linkage is actually an amide linkage formed between Carboxyl group of one Amino acid and the Amino group of other Amino acid.