Question

Identify the correct statement for change of Gibbs
energy for a system (ΔG????y????????????m) at constant
temperature and pressure
(a) If ΔG????y????????????m = 0, the system has attained equilibrium
(b) If ΔG????y????????????m = 0, the system is still moving in a particular direction
(c) If ΔG????y????????????m < 0, the process is not spontaneous
(d) If ΔG????y????????????m > 0, the process is not spontaneous

Answer 1

Answer:

You have not even the options properly so tried to give it properly

Answer 2

Complete question:

Identify the correct statement for change of Gibbs energy for a system (ΔG(system)) at constant temperature and pressure:

(a) If (ΔG(system)) = 0, the system is still moving in a particular direction

(b) If (ΔG(system)) = + ve, the process is not spontaneous

(c) If (ΔG(system)) = - ve, the process is spontaneous

(d) If (ΔG(system)) = 0, the system has attained equilibrium

Answer:

The correct statement is (d) If (ΔG(system)) = 0, the system has attained equilibrium.

Explanation:

Option (a):

When ΔG(system) = 0, then the system is in equilibrium.

In equilibrium, Product ⇄ reactant

The system is not in a particular direction. This is not the correct option.

Option (b):

When ΔG(system) = + ve, then the system is spontaneous.

This is not the correct option.

Option (c):

When ΔG(system) = - ve, then the system is non-spontaneous.

This is not the correct option.

Option (d):

When ΔG(system) = 0, then the system is in equilibrium.

This is the correct option.