Identify the element undergoing oxidation in the given equation;
CuO + H2 → Cu + H20
a) cu b) h2o c) cuO d) h2
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The element is H2...because in the reactant side it is getting oxidised..
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H2 is getting oxidised cuz it’s charge on reactant side is 0
Whereas in product side it is -2
As overall charge on H20 is 0
Charge on O=-2
Charge on O+Charge on H2=0
-2+charge on H2=0
Charge on H2= -2
Whereas in product side it is -2
As overall charge on H20 is 0
Charge on O=-2
Charge on O+Charge on H2=0
-2+charge on H2=0
Charge on H2= -2
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