Question

identify the excess reagent where 8g of CH4 burnt using 20g of O2 and also calculate amount of excess reagent left

Answer 1

Answer:

The reaction is CH

4

+2O

2

→CO

2

+2H

2

O.

At room temperature, water will condense to form liquid water.

1 mole of methane reacts with 2 moles of oxygen to form 1 mole of oxygen.

10 ml (0.445 moles) of methane will react with 20 ml (0.89 moles) of oxygen to form 10 ml (0.445 moles) of carbon dioxide.

Hence, the resulting mixture will contain 10 ml of unreacted methane and 10 ml of carbon dioxide.

The total volume of the mixture will be 20 ml.