identify the following reaction for between lead sulphide and hydrogen peroxide. 1.write the chemical equation for our given condition.
2. which substance is reducing agent.
3. which substance is oxidising agent.
4. identify identify the compound which are oxidized and reduced.
Answers
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Explanation:
a) H2O2 is reduced to H2O.
b) PbS is oxidised to PbSO4.
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Answer:
Explanation:
In the following reaction between lead sulphide and hydrogen peroxide.
PbS(s)+4H 2 O2 (aq)→PbSO 4 (s)+4H2 O(l)
a) Which substance is reduced?
b) which substance is oxidisd?
Answer
a) H 2 O 2 is reduced to H 2 O.
b) PbS is oxidised to PbSO 4.
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