English, asked by Anonymous, 3 months ago

Identify the haloalkane that does not undergo β-elimination reaction on treatment with alcoholic KOH

Answers

Answered by aliabhatt30

2

Answer:

Haloalkanes in the presence of alcoholic KOH undergoes elimination reaction or dehydrohalogenation reaction.

CH

3

CH

2

CH

2

Br+alc.KOH→CH

3

CH=CH

2

+KBr+H

2

O

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