Question

Identify the hybridization of the N atoms in N2H4

Answer 1

Answer:

In fact, there is sp3 hybridization on each nitrogen. Considering the lone pair of electrons also one bond equivalent and with VSEPR Theory adapted, the NH2 and the lone pair on each nitrogen atom of the N2H4 molecule assume staggered conformation with each of H2N-N and N-NH2 segments existing in a pyramidal structure

Answer 2

HYBRIDIZATION -

• The phenomenon of combining atomic orbitals to form new hybridized orbitals.
• The hybridized orbitals possess different bonding properties.
• It helps to explain the shape of the molecular orbitals.
• In the compound$N_2H_4$, two nitrogen atoms are bonded together containing one lone pair and each attaching two hydrogen atoms.
• The lewis dot structure shows the presence of 2 lone pairs and 5 bond pairs.
• The formal charge on hydrazine is zero.
• The hybridization of each nitrogen atom is $sp^3$.
• The molecular and electron geometry of the $sp^3$hybridization is trigonal pyramidal.