Identify the incorrect expression for solution of monoacidic base (BOH) [Kb is base dissociation constant of BOH and K, is hydrolysis constant of B*]
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Answer:
Explanation:
Base, BOH is dissociated as follows
BOH⇌B++OH−
So, the dissociation constant of BOH base
Kb=[B+][OH−][BOH]..........(i)
At equilibrium [B+]=[OH−]
∴Kb=[OH−]2[BOH]
Given that Kb=1.0×10−12
and [BOH]=0.01M
Thus, 1.0×10−12=[OH−]20.01
[OH−]2=1×10−14
[OH−]=1.0×10−7molL−1
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