Question

Identify the least number must be added to 1057 so that the sum is completely divisible by21

Answer 1

Answer:

14 to be added

Step-by-step explanation:

if we divide 1057 by 21

we get 7 as remainder

To get divided by 21 we need to add

21-7 = 14

number would be 1071

Answer 2

Answer:

The least number which must be added to 1057 such that it is divisible by 21 = 14

Step-by-step explanation:

The given number is given to be 1057

Now we have to find the least number which should be added to 1057 such that it is completely divisible by 21

For this, first divide the given number 1057 by 21 and find out the remainder.

So, 1057 = 21 × 50 + 7

⇒ Remainder = 7

So, to make it divisible by 21 add (21 - 7) = 14 to the number

So, The number becomes 1057 + 14 = 1071

And, 1057 = 21 × 51 + 0

Hence, The least number which must be added to 1057 such that it is divisible by 21 = 14