Identify the limiting reagent if 1 mole of carbon burns in 16 g of air
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when 1 mole of carbon is burnt in 1 mole(32 g) of air(dioxygen) ,then according to chemical equation (1) 1mole(44 g) of carbon dioxide is produced. (iii) According to the question, only 16 g of dioxygen is available. It is a limiting reactant
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Answer:
the limiting reagent is 3:4
Explanation:
molar mass of 1 mole carbon = 12g
air = 16g
then,
12:16 = 12/16
= 3:4
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