Question

identify the missing product in the below reaction carried in liquid ammonia NH4CL + KNH2

Answer 1

The product formed will be potassium chloride and ammonia.

• The reaction happening is between ammonium chloride and potassium amide.
• There will be displacement of anions and cations from each other in these compounds, thus it will be a double displacement reaction.
• The reaction is as follows:

$NH_{4}Cl+KNH_{2}$ → $KCl+2NH_{3}$

• If one mole of ammonium chloride and potassium amide is reacted, then there will be the formation of one mole of potassium chloride and the evolution of ammonia gas.