Identify the number who's prime factorization has three 2's, two 3's and a 5
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❥ Question :
Identify the number who's prime factorization has three 2's, two 3's and a 5
❥ Given :
Factorization consists three 2's, two 3's and a 5
❥ Answer :
Three 2's, Two 3's and One 5 = 2 × 2 × 2 × 3 × 3 × 5
Let the number be x.
x = Factorization of x
x = 2 × 2 × 2 × 3 × 3 × 5
= 360
Thus the required number is 360
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