Identify the oxidising agent in the following reaction:
1)Pb3O4+8HCl=3PbCl2+Cl2+4H2O
2)ZnO+H2=Zn+H2O
3)3Fe+4H2O=Fe3O4+4H2
4)V2O5+5Ca=2V+5CaO
Answers
Answered by
2
Answer:
1)Pb3O4 + 8HCl → 3PbCl2 + Cl2 + 4H2O
Oxidizing agent : Pb3O4
2)ZnO + H2 → Zn + H2O
Oxidizing agent : ZnO
3)3Fe + 4H2O → Fe3O4 + 4H2
Oxidizing agent : H2O
4)V2O5 + 5Ca → 2V + 5CaO
Oxidizing agent : V2O5
Explanation:
An oxidizing agent removes electrons from reactants, gains electrons and gets reduced itself.
Similar questions