Question

identify the oxidizing agent (oxidant) in the following reaction. 1)pb3o4+8HCl=3pbcl2 +Cl2+H2O. 2) 3Fe +4H2O= Fe3O4+4H2. 3) V2O5+5Ca= 2V+5CaO. 4) CuSO4+Zn= Cu+ZnSO4​

Answer 1

Answer:

Oxidising agents :

a) Pb3O4

b) H2O

c) CuSO4

d) V2O5

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Explanation:

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Answer 2

Answer:

1) Pb3O4

2) H2O

3) V2O5

4) CuSO4

Explanation:

Oxidising agent in a reaction is the one which gets reduced and oxidises other reactant.

1) Pb3O4 + 8HCl = 3PbCl2 + Cl2 + H2O.

Pb: +8/3 to +2 (reduced)

Cl : -1 to 0 (Cl2)

Hence Pb3O4 is oxidising agent

2) 3Fe + 4H2O = Fe3O4 + 4H2.

Fe: 0 to +8/3 (oxidised)

H : +1 to 0 (reduced)

Hence H2O is the oxidizing agent

3) V2O5 + 5Ca = 2V + 5CaO.

V: +5 to 0 (reduced)

Hence V2O5 is oxidising agent

4) CuSO4 + Zn = Cu + ZnSO4

Zn : 0 to +2

Cu : +2 to 0 (reduced)

CuSO4 is oxidising agent.