Identify the polarity and met dipole moment
for the following molecules ; [the answer
must include the VSEPR structure
@ H₂O
(6) ASES
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Answered by
1
Answer
Correct option is
A
BF
3
<H
2
S<H
2
O
In BF
3
, dipole moment is zero due to its symmetrical structure. Summations of all dipoles are zero.
In H
2
S and H
2
O due to unsymmetrical structure net +ve dipole is there. H
2
O has a higher dipole due to the higher electronegativity of oxygen than sulphur.
Hence, the correct order is: BF
3
<H
2
S<H
2
O.
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