Question

Identify the reductant and oxidant :. :2Na + Cl2 → 2NaCl *
1 point
Reductant : Ci , Oxidant : Na
Reductant : Na , Oxidant : Cl
Reductant : Cl , Oxidant : NaCl
Reductant : Na , Oxidant : NaCl​

Answer 1

Answer:

We have the balanced equation:

We have the balanced equation:2Na(s)+Cl2(g)→2NaCl(s)

We have the balanced equation:2Na(s)+Cl2(g)→2NaCl(s) Na(0) gets oxidized to Na(I) , while Cl(0) gets reduced to Cl(−I) .

gets reduced to Cl(−I) .Since sodium got oxidized, it is the reducing agent in this equation.

gets reduced to Cl(−I) .Since sodium got oxidized, it is the reducing agent in this equation.It doesn't matter if there was one sodium or three sodium atoms, the reducing agent is just the element or molecule itself, so

gets reduced to Cl(−I) .Since sodium got oxidized, it is the reducing agent in this equation.It doesn't matter if there was one sodium or three sodium atoms, the reducing agent is just the element or molecule itself, so Na

gets reduced to Cl(−I) .Since sodium got oxidized, it is the reducing agent in this equation.It doesn't matter if there was one sodium or three sodium atoms, the reducing agent is just the element or molecule itself, so Na will be the reducing agent here.

Explanation:

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