Question

Identify the substance oxidised and the substance reduced in the following h2(g) + cl2(g)=2hcl(g)

Answer 1

Answer:

Substance oxidized : H₂ ; Substance reduced : Cl₂

Explanation:

Answer 2

$\large{\bf{\gray{\underline{\underline{\orange{Given:}}}}}}$

$\dag\:\boxed{\bf{\gray{H_2(g)+Cl_2(g)\:\longrightarrow\:2HCl(g)}}}$

$\large{\bf{\gray{\underline{\underline{\green{To\:Find:}}}}}}$

We have to identify the substance which is oxisidised and the substance which is reduced in the given chemical reaction.

$\large{\bf{\gray{\underline{\underline{\pink{Solution:}}}}}}$

➠ In terms of electron transfer, loss of electrons by any species is called oxidation (increse in oxidation number) and gain of electron by any species is called reduction (decrease in oxidation number).

➝ Oxidaion number of H in $\sf{H_2}$ = 0

➝ Oxidation no. of H in $\sf{HCl}$ = (+1)

➝ Oxidation no. of Cl in $\sf{Cl_2}$ = 0

➝ Oxidation no. of Cl in $\sf{HCl}$ = (-1)

Therefore,

Oxidised substance = $\bf{H_2}$

Reduced substance = $\bf{Cl_2}$