Chemistry, asked by narpat4111, 1 year ago

Identify the substance oxidised and the sunstance reduced in each reaction. 1. CuO + H2---Cu+H2O, 2. ZnO+C---Zn+CO,3. MNO2+4HCL---MnCl2+2H2O+Cl2

Answers

Answered by abuahmed2200a
0

● Some Oxidation numbers roles as

☆The element oxidation no is zero

☆The total sum of oxidation no of compound is equal zero

☆The total sum of oxidation no of ion is equal the charge of ion

☆The oxidation process in which the element oxidation no increases

☆The rexuction process in which the element oxidation no decreases

◇ CuO+ H2 => Cu + H2O

• CuO = zero

Cu = +2 , O = -2

• H2 = zero

• Cu

• H2O = zero

H = +1 , O= -2

■ Cu decrease the oxidation no so its reduced

■ H increases the oxidation no so its oxidized

The next equation

♤ Zn changes from +2 to zero , decreases so its reduced

♤ C changes from zero to +2 so its oxidized

The next equation

♧ Mn changes from +4 to +2 , its decreases, so its reduction

♧ Cl changes from -1 to zero , increases , so its oxidation

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