Question

Identify the substance reduced ,substance oxidized, oxidizing agent ,reducing agent in the given equation 2CU 2o + CU 2S gives 6CU + SO2

Answer 1

2CuO + C ---> 2Cu ( after balancing)

• Oxidised substance = Cu
• Reduced substance= O₂
• Oxidising agent= O₂
• Reducing agent= Cu

Answer 2

Answer:

Hope it helps

substance reduced = CuO

substance oxidized = S

oxidizing agent = CuO

reducing agent = S

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