Chemistry, asked by yadavsnehasneha5812, 1 year ago

Identify the substance that is oxidized and reduced in the reaction -
CuO(s) +Zn(s) --->Cu (s) +ZnO(s)

Answers

Answered by Evanbo222
1

Answer:

Zn is oxidised to form ZnO & CuO is reduced to form Cu.

Explanation:

Oxidation:

  • According to classical or previous concepts, oxidation is a process in which oxygen or any other electronegative element is added, while hydrogen or another electropositive element is removed.
  • However, according to the electronic concept, oxidation is the process by which an atom or an ion loses one or more electrons.

Reduction:

  • According to classical or older concepts, reduction is a process that involves the addition of hydrogen or any other electropositive element or the removal of oxygen or any other electronegative element.
  • However, according to the electronic concept, reduction is the process through which an atom or an ion gains one or more electrons.

In the given reaction,

CuO (s) + Zn(s) ⇒ Cu (s) + ZnO (s)

Zn is oxidised to form ZnO (because oxygen is added)

& CuO is reduced to form Cu (because oxygen is removed).

#SPJ3

Answered by rahul123437
0

Zn is oxidised to form ZnO & CuO is reduced to form Cu.

Explanation:

Oxidation:

According to classical or previous concepts, oxidation is a process in which oxygen or any other electronegative element is added, while hydrogen or another electropositive element is removed.

However, according to the electronic concept, oxidation is the process by which an atom or an ion loses one or more electrons.

Reduction:

According to classical or older concepts, reduction is a process that involves the addition of hydrogen or any other electropositive element or the removal of oxygen or any other electronegative element.

However, according to the electronic concept, reduction is the process through which an atom or an ion gains one or more electrons.

In the given reaction,

CuO (s) + Zn(s) ⇒ Cu (s) + ZnO (s)

Zn is oxidised to form ZnO (because oxygen is added)

& CuO is reduced to form Cu (because oxygen is removed).

#SPJ3

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