Question

Identify the substance that is oxidized and the substance that is reduced in the reaction.CuO(s)+H2(g)=Cu(s)+H2O(l)

Answer 1

In the above reaction copper oxide is reduced to copper and hydrilla gas is oxidized to water

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Answer 2

The substance oxidized is H2.
The substance reduced is CuO.
Therefore, H2 is the reducing agent.
And, CuO is the oxidizing agent.