Question

Identify the substances that are oxidized and that are reduced in the following equation.

i) 4Na(s) + O2(g) → 2Na2O(s)

ii) CuO(s) + H2(g) → Cu(s) + H2O(l)

​

Answer 1

Answer:

The Sodium (Na) in the first equation is getting oxidized with the addition of Oxygen (O2) and the Copper (Cu) in the second equation is reduced due to the addition of Hydrogen (H2)

Answer 2

Answer:

1 na has gained o2 to form na20.. hence  na has been oxidised to na2o...therefore o2 has been reduced

2  cuo has lost  o2 to form cu.hence  cuo has been reduced to cu.h2 has gained o2 to form h20 ..hence h2 has been oxidised to h20