Question

Identify the substances that are oxidized and that are reduced in the following equation.
i) 4Na(s) + O2(g) → 2Na2O(s)
ii) CuO(s) + H2(g) → Cu(s) + H2O(l)

Answer 1

$\huge\mathbb\pink{Question:-}$

Identify the substances that are oxidized and that are reduced in the following equation.

i) 4Na(s) + O2(g) → 2Na2O(s)

ii) CuO(s) + H2(g) → Cu(s) + H2O(l)

$\huge\mathbb\blue{Answer:-}$

The Sodium (Na) in the first equation is getting oxidized with the addition of Oxygen (O2) and the Copper (Cu) in the second equation is reduced due to the addition of Hydrogen (H2)

Answer 2

Answer:

i) Na is oxidised and O2 is reduced.

ii) H2 is oxidised and Cu is reduced.

hope it helps...............:)