identify the sum of X, Y, Z from the following figure?
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x=y= 40,z=70 OK Dear
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√√ Parallel Lines √√
--> CBE = 70°
=> 180 - CBE = 110°
=> ABE = 110°
=> x = 150 - ABE = 40° √√
--> AE || BD -> BE is the transversal
=> ∠AEB = ∠EBD ------> [ alternate - interior angles ]
=> x = y = 40° √√
--> BE || CD
--> ∠ABE = ∠ACD ---> [ corresponding angles ]
=> z = 110°
Hence, Sum [ x , y , z ] = [ 110° + 40° + 40° ] = 190° √
--> CBE = 70°
=> 180 - CBE = 110°
=> ABE = 110°
=> x = 150 - ABE = 40° √√
--> AE || BD -> BE is the transversal
=> ∠AEB = ∠EBD ------> [ alternate - interior angles ]
=> x = y = 40° √√
--> BE || CD
--> ∠ABE = ∠ACD ---> [ corresponding angles ]
=> z = 110°
Hence, Sum [ x , y , z ] = [ 110° + 40° + 40° ] = 190° √
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