Question

identify the type of isomerism exhibited by the following pairs ch3ch2ch2oh and ch3ch-ch3
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oh

Answer 1

Answer:

Its Positional isomerism.

Explanation:

n-propyl alcohol :CH3–CH2–CH2–OH

and isopropyl alcohol: CH3–CH(OH)–CH3

No. of C is same in both but the position of functional group is altered.

Answer 2

Answer:

1-propanol and 2-propanol are positional isomers and exhibit positional isomerism.

Explanation:

Isomerism: Isomerism is described as the phenomenon in which more than one chemical compounds have the same molecular formula but differs in properties and chemical structures.

1) CH₃CH₂CH₂OH

• IUPAC name → propan-1-ol or 1-propanol
• Common name → n-propanol 
• This compound is a primary (1°) alcohol.
• In this, the hydroxyl group, i.e., the -OH group is present at the primary carbon atom, which makes it primary alcohol.

2) CH₃CH(OH)CH3

• IUPAC name → propan-2-ol or 2-propanol
• Common name → n-propanol 
• This compound is secondary (2°) alcohol.
• In this, the hydroxyl group, i.e., the -OH group is present at the secondary carbon atom, which makes it secondary alcohol.

Here, IUPAC = International Union of Pure and Applied Chemistry

In the given compounds,

• The functional group present in both the compounds is the hydroxyl group, i.e., the -OH group.
• Both the compounds have the same molecular formula C₃H₈O.
• Both the compounds differ only in the position of the hydroxyl group, i.e., the -OH group.
• In the first compound, i.e., in 1-propanol, the -OH group is attached to the primary carbon and in the second compound, i.e., in 2-propanol, the -OH group is attached to the secondary carbon.

Hence, we can say that,

• 1-propanol and 2-propanol are positional isomers.