Math, asked by herilchahwala, 1 year ago

Identify the type of polynomials.

(1). f(p) =3-p²+√7p
(2). p(v)=√3v⁴-⅔v+7
(3). q(x)=√2/5x³+1
(4). p(z)=√5z+2√2
(5). r(t)=(-t+3t²-4t³) /t

Answers

Answered by renuagrawal393
19

Answer:

1.quadratic

2.biquadratic

3.cubic

4.linear

5.quadratic

hope it helps you.....

Answered by SteffiPaul
1

(1.) Therefore f(p) =3-p²+√7p is a 'Quadratic Polynomial'.

(2.) Therefore p(v)=√3v⁴-⅔v+7 is a 'Bi-Quadratic Polynomial'.

(3.) Therefore q(x)=√2/5x³+1 is a 'Cubic Polynomial'.

(4.) Therefore p(z)=√5z+2√2 is a 'Linear Polynomial'.

(5.) Therefore r(t)=(-t+3t²-4t³) /t is a 'Quadratic Polynomial'.

Given:

(1). f(p) =3-p²+√7p

(2). p(v)=√3v⁴-⅔v+7

(3). q(x)=√2/5x³+1

(4). p(z)=√5z+2√2

(5). r(t)=(-t+3t²-4t³) /t

To Find:

The type of each of the polynomials given.

Solution:

The given question can be solved as shown below.

(1.) f(p) =3-p²+√7p:

In the given polynomial, the greatest power of p is '2'. So the given polynomial is a 'Quadratic Polynomial'.

Therefore f(p) =3-p²+√7p is a 'Quadratic Polynomial'.

(2). p(v)=√3v⁴-⅔v+7:

In the given polynomial, the greatest power of v is '4'. So the given polynomial is a 'Bi-Quadratic Polynomial'.

Therefore p(v)=√3v⁴-⅔v+7 is a 'Bi-Quadratic Polynomial'.

(3). q(x)=√2/5x³+1:

In the given polynomial, the greatest power of x is '3'. So the given polynomial is a 'Cubic Polynomial'.

Therefore q(x)=√2/5x³+1 is a 'Cubic Polynomial'.

(4). p(z)=√5z+2√2:

In the given polynomial, the greatest power of z is '1'. So the given polynomial is a 'Linear Polynomial'.

Therefore p(z)=√5z+2√2 is a 'Linear Polynomial'.

(5). r(t)=(-t+3t²-4t³) /t:

r(t)=(-t+3t²-4t³) /t = -1 + 3t - 4t²

In the given polynomial, the greatest power of t is '2'. So the given polynomial is a 'Quadratic Polynomial'.

Therefore r(t)=(-t+3t²-4t³) /t is a 'Quadratic Polynomial'.

(1.) Therefore f(p) =3-p²+√7p is a 'Quadratic Polynomial'.

(2.) Therefore p(v)=√3v⁴-⅔v+7 is a 'Bi-Quadratic Polynomial'.

(3.) Therefore q(x)=√2/5x³+1 is a 'Cubic Polynomial'.

(4.) Therefore p(z)=√5z+2√2 is a 'Linear Polynomial'.

(5.) Therefore r(t)=(-t+3t²-4t³) /t is a 'Quadratic Polynomial'.

#SPJ2

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