Question

Identify the type of reactions taking place in each of following cases and
write the balanced chemical equation for the reactions.
a) Zn reacts with silver nitrate to produce zinc nitrate and silver.
b) Potassium iodine reacts with lead nitrate to produce potassium
nitrate and lead iodide ?​

Answer 1

Here's your answer

a) Displacement Reaction.

Since zinc is more reactive than silver, it displaces silver from the compound to form zinc nitrate.

Zn + Ag(NO3)2 -------> Zn(NO3)2 + Ag

b) Double displacement reaction.

KI + Pb(NO3)2 -------> KNO3 + PbI2

Hope this helps!

Answer 2

For a: The reaction is a single displacement reaction

For b: The reaction is a double displacement reaction

Explanation:

A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.

• For a:

The chemical equation for the reaction of zinc with silver nitrate follows:

$Zn+2AgNO_3\rightarrow Zn(NO_3)_2+2Ag$

The above reaction is an example of single displacement reaction because here, more reactive element displaces a less reactive element from its chemical reaction.

• For b:

The chemical equation for the reaction of potassium iodide with lead nitrate follows:

$2KI+Pb(NO_3)_2\rightarrow 2KNO_3+PbI_2$

The above reaction is an example of double displacement reaction because here, exchange of ions takes place.

Learn more about single displacement and double displacement reactions:

https://brainly.com/question/2121089

https://brainly.com/question/12049042

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