Identity (a-b) whole square
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(a-b)^2 = a^2 + b^2 - 2ab
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How this identity of (a - b)2 = a2 + b2 - 2ab is obtained:
Taking LHS of the identity:
(a - b)2
This can also be written as:
= (a - b) (a - b)
Multiply as we do multiplication of two binomials and we get:
= a(a - b) - b(a - b)
= a2 - ab - ab + b2
Add like terms and we get:
= a2 - 2ab + b2
Rearrange the terms and we get:
= a2 + b2 - 2ab
Hence, in this way we obtain the identity i.e. (a - b)2 = a2 + b2 - 2ab
Taking LHS of the identity:
(a - b)2
This can also be written as:
= (a - b) (a - b)
Multiply as we do multiplication of two binomials and we get:
= a(a - b) - b(a - b)
= a2 - ab - ab + b2
Add like terms and we get:
= a2 - 2ab + b2
Rearrange the terms and we get:
= a2 + b2 - 2ab
Hence, in this way we obtain the identity i.e. (a - b)2 = a2 + b2 - 2ab
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