Question

Identity and find the product of (3k +4l) (3k+4l)

Answer 1

=(3k+4l) (3k+4l)
=9k+12kl+12kl+16l^2
=9k+24kl+16l^2

Answer 2

Use - $(x + y)^2 = x^2 + 2xy + y^2$

Step-by-step explanation:

The given terms (3k + 4l) (3k + 4l) means any two expressions (Binomial) are multiplied together.

Apart from that there terms are same i.e. 3k + 4l

On comparison of the identities & the expressions we know that -

$(x+y)^2$

becomes the valid form.

And x = 3k & y = 4l

• The identity $(x + y)^2 = x^2 + 2xy + y^2,$

Thus,$(3k + 4l)(3k + 4l) = (3k + 4l)^2 = (3k)^2 + 2(3k)(4l) + (4l)^2 = 9k^2 + 24kl + 16l^2$