Identity of a^3+b^3?????
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Answered by
4
Hey mate....
Here is your answer ;
= 
Hope it helps you....
Here is your answer ;
Hope it helps you....
Shaanraj:
plz Mark me the brainliest...
How can i do it
you can do it by a cyclic algorithm...
you can add and subtract 3ab(a + b)
Answered by
2
a^3+b^3
=(a + b)^3 -3ab(a + b)
= a^3 + b^3 + 3ab( a+ b ) -3ab(a+b)
=a^3 + b^3 +0. [3ab(a+b) - 3ab(a+b) =0]
Hence,LHS = RHS
or,
a^3 + b ^3 = (a - b)(a^2+ab + b^2)
I hope it is helpful!!!
=(a + b)^3 -3ab(a + b)
= a^3 + b^3 + 3ab( a+ b ) -3ab(a+b)
=a^3 + b^3 +0. [3ab(a+b) - 3ab(a+b) =0]
Hence,LHS = RHS
or,
a^3 + b ^3 = (a - b)(a^2+ab + b^2)
I hope it is helpful!!!
absolutely wrong sorry
What
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