If () = {, ≤0 0, > 0 , then at x=0
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f is not differentiable at x=0
x→0+limxxa=axa−1
=x1−aa
In the denominator 1−a>0 since 0<a<1.
Now when substituting the limit we get it as undefined,hence the given function is not differentiable at x=0.
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