If (0,0)is the centre of a circle and (2,3) is one endpoint of its diameter then find the other end point.
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One end of diameter of the circle =(3,2)
Center of the circle =(0,0)
Let, the other end of diameter of the circle =(x,y)
Since , center is the mid-point of the diameter of the circle
(0,0)=( 23+x , 22+y )
⟹ 23+x =0 and 22+y =0
⟹3+x=0 and 2+y=0
⟹x=−3 and y=−2
Hence, the other end of diameter of the circle =(−3,−2)
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One end of diameter of the circle = (3,2)
Center of the circle = (0,0)
Let, the other end of diameter of the circle = (x,y)
Since , center is the mid-point of the diameter of the circle
- (0,0)=( 3+x / 2 , 2+y / 2)
- 23+x =0 and 22+y =0
- 3+x=0 and 2+y=0
- x=−3 and y=−2
Hence, the other end of diameter of the circle =(−3,−2)
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