if 0, 0 shifted to a point on x-axis then 2 X + 3 Y - 6 is equal to zero reduced as Lx+ my=0 is
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Answered by
1
Answer:
Concept: Slope of general equation of line ax+by+c=0 is m=−coefficient of ycoefficient of x
Therefore,
Slope of line 2x+3y−3=0 is =−32
and slope of line x+ky+7=0 is −k1
Now we know that two lines are perpendicular if their product of slopes is −1
⇒−32×−k1=−1
⇒k=−32
Answered by
0
Answer:
(3,0)
Step-by-step explanation:
Let (X,Y) be the new coordinates of the point ( X,y)
x = X + h , Y = Y + k
X = x-a , Y = y- k
2(X +a) + 3y-6 = 0
2x+3y+2a+6 =0
2a - 6 = 0
a= 3
So the required point is (x,y) = (3,0)
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