If 0.01 M solution of an electrolyte has a resistance of 40
ohms in a cell having a cell constant of 0.4 cm⁻¹, then its
molar conductance in ohm⁻¹ cm² mol⁻¹ is
(a) 10² (b) 10⁴
(c) 10 (d) 10³
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The Molar conductance of the solution is 10³.
Quantity of solution = 0.01M (Given)
Resistance = 40 ohms (Given)
Cell constant = 0.4 cm⁻¹, (Given)
Thus,
The molar conductance will be calculated as -
= 1/ Resistance × Cell constant / Mol concentration
= 1/40 × 0.4 / 0.01 × 10`³
= 10³
Therefore, the concentration of the mole is 10³cm²mol.
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