Question

If 0.01 m solution of an electrolyte has a resistance of 400 in a cell having a cell constant 0.4 then its molar conductance

Answer 1

Answer:

The molar conductance of the solution is $100 S cm^2 /mol$.

Explanation:

Cell constant of the cell =$K_{cell}=\frac{length}{Area}=0.4 cm^{-1}$

Resistance offered by the solution = 400 Ω

Specific conductance$\kappa =\frac{1}{R}\times K=\frac{1}{400}\times 0.4cm^{-1}=0.001 S cm^{-1}$

Molar conductance $\Lambda _m=\frac{\kappa \times 1000}{molarity}$

$\Lambda _m=\frac{0.001 S cm^{-1}\times 1000}{0.01 M}=100 S cm^2/mol$

The molar conductance of the solution is $100 S cm^2 /mol$.