if 0.08 Mole of HNO3 is required how many grams of HNO3 should be taken
(atomic mass of some elements: c=12,O=16,H=1,N=14)
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Answer: 5.04g
Explanation: mole=0.08
Molecular mass=63
Mass in gram=?
Mole = mass/molecular mass
0.08 = mass/63
Mass = 63×0.08
Mass 5.04g
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