Question

if (0, 1 )and (1, 1) end points of a diameter of a circle then its equation is

Answer 1

${(x - 0)}^{2} {(x - 1)}^{2} + {(y -1) }^{2} {(y - 1)}^{2} = 0 \\ solve \: to \: get \: the \: equation$