Question

If 0.1 m of a weak acid is taken and its percentage of degree of ionization is 1.34%1.34%, then its ionization constant will be

Answer 1

Answer:

According to Ostwald's dilution law

Ka = Cα²/(1−α)

Ka = Cα²

α = √ka/C *C = 0.1m

α = 1.34

ka = 0.1×(1.34×10^−2)² = 1.79 × 10^−5 (Ans.)

Answer 2

Using Ostwald's dilution law :

• Ka = Cα²/(1−α)

• Ka = Cα² [ Relation ]

• α = √ka/C *C = 0.1m

• α = 1.34

• ka = 0.1×(1.34×10^−2)²

• 1.79 × 10^−5

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