Question

If 0.15 g sample of zinc ore was brought in solution as ZnCl₂ and the zinc salt separated and treated with ferrocyanide solution as, 2K4[Fe(CN)6] +3ZnCl₂ K₂Zn3[Fe(CN)6]2+ 6KCI 25 ml of 0.01 M ferrocyanide solution was required. Determine percentage of zinc in the ore. (Zn = 65)​

Answer 1

Given:

If $0.15 g$ sample of zinc ore was brought in solution as $ZnCl_{2}$ and the zinc salt.

To find:

Determine percentage of zinc in the ore. $Zn = 65$.

Explanation:

molar mass of $2nCl_{2}$

 $=65$

moles=$0.15/65$

$=0.00023$

molarity=$0.01m$​

Δ

  ⇋

a         0     0

a-a a

total moles of equations

$\alpha -0.735$

%$=73.5$%

Answer:

Therefore, The Determine percentage of zinc in the 73.5%.